Hi…
Does anyone know if it is possible to selectively avoid HSR on a polygon? I would like to see if transparency effects implemented in a glsl fragment shader are possible but from the architecture guide I gather geometry is always subject to HSR unless blending or alpha testing is enabled or there are discards in the fragment shader. In practice I suspect the default alpha blending might be fine… at this point I’m just curious.
Any help would be appreciated…
Thanks
Hi wrabbit,
There is no way to disable the HSR for opaque geometry. Can you explain why you would want to disable the HSR? It’s an extremely fast operation and is very unlikely to cause a bottleneck in an application.
Thanks,
Joe
ok.. if there is no performance/power gain to be had in disabling HSR then that's fine.
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MicrosoftInternetExplorer4
Hi wrabbit,
You should refer to our "SGX Architecture Guide for Developers"
document
here for
more information on how HSR works. From an application's point of view, there is no difference between an image rendered with HSR enabled or rendered with it disabled. HSR is a hardware level optimization to reduce overdraw.
From my understanding, the Adaptive Transparency technique relies on the DX11
per-pixel linked list functionality. The current OpenGL ES APIs do not have any
mechanisms for building per-pixel linked lists to specify rendering order.
Because of this, the technique will be difficult to implement in the current
OpenGL ES APIs without incurring a significant performance overhead.
Thanks,
Joe
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